Question

关于三角形的高、中线与角平分线的问题

Answer 1

∠C=∠B+90°

∠AEC=∠B+1/2∠BAC

在△AEC中,

∠C+1/2∠BAC+∠AEC=180

(∠B+90°)+1/2∠BAC+∠AEC=180°

(∠B+1/2∠BAC)+∠AEC=90°

∠AEC+∠AEC=90°

∠AEC=45°