sin2π/3=?;cos2π/3=?;sin7π/6=?;cos7π/6=?说下
3个回答
sin2π/3=sinπ/3=√3/2
cos2π/3=-cosπ/3=-1/2
sin7π/6=-sinπ/6=-1/2
cos7π/6=-cosπ/6=- √3/2
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