1.由(a- b)^2+|b-4|=0 ,得a=b=4,
∴A(4,0),b(0,4).
2.C(3,1).设P(0,p),p>0,
CP的斜率k1=(1-p)/3,CO的斜率k2=1/3,
tanOCP=(k2-k1)/(1+k2k1)=(p/3)/[1+1/3*(1-p)/3]=3p/(10-p)=1,
3p=10-p,p=2.5.
∴P(0,2.5).
3.作CH⊥OA于H,则H(3,0)在A,E之间,
易知△BOD∽△CHE∽△OHC,
∴OD/OB=HE/HC=HC/HO=1/3,
∴OD=4/3,HE=1/3,
∴AE=AH+HE=4/3=OD.