Question

解一元一次方程：（1）3x-(2x-7)=-1 （2）7x-2(x-1)=-3 （3）2(3-y)-3(2/3y+1)=

Answer 1

(1)3x-(2x-7)=-1

3x-2x+7=-1

x=-8

(2)7x-2(x-1)=-3

7x-2x+2=-3

5x=-5

x=-1

(3)2(3-y)-3(2y/3+1)=1

6-2y-2y-3=1

-4y=-2

y=1/2

(4)9(2x/3+1)-2(x-1/2)=-2

6x+9-2x+1=-2

4x=-12

x=-3