(1)5-(3+2i) =5-3-2i=2-2i (2)(-3-4i)+(2+i)-(1-5i) =-3-4i+2+i-1+5i=-2+2i (3)(2-i)-(2+3i)+4i =2-i-2-3i+4i=-4i+4i=0
计算:(1)5-(3+2i) (2)(-3-4i)+(2+i)-(1-5i) (3)(2-i)-(2+3i)+4i
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