Question

如图12—7—10,p、q是△abc的边bc上的两点,且bp=pq=qc=ap=aq,则∠abc的度数是

Answer 1

已知：bp=pq=qc=ap=aq,则

△apq为等边三角形,每个角就为60°,

∠apc=60°=∠abc+∠bap

bp=ap,则

△abp为等腰三角形,即∠abc=∠bap

2∠abc=60°

∠abc=30°