Question

已知平行四边形ABCD中P为对角线AC上任一点,求S△ABP：S△ADP

Answer 1

S△ABP：S△ADP=1

分析：S△ABP=AP*h(△ABP)/2; S△ADP=AP*h(△ADP)/2

所以S△ABP：S△ADP=[AP*h(△ABP)/2; ]:[AP*h(△ADP)/2]=h(△ABP):h(△ADP)=1:1