Question

求使分式(m^2-n^2/a^2m-a^2n)*(am+an)/(m+n)^2的值等于5的a值为?

Answer 1

(m^2-n^2/a^2m-a^2n)*(am+an)/(m+n)^2

=((m+n)(m-n)/a^2(m-n))*(a(m+n)/(m+n))

=1/a

=5

a=1/5