Question

计算：{-1/4a^(3-n)b^(m-1)}^2·（4a^(3+n)b)^2

Answer 1

{-1/4a^(3-n)b^(m-1)}^2·（4a^(3+n)b)^2

=[-1/4a^(3-n)b^(m-1)*4a^(3+n)b]²

=[-a^(3-n+3+n)b^(m-1+1)]²

=[-a^6b^m]²

=a^12b^2m