计算:16^(3/4) *(1/2)^2 +2lg根号2 +(1/2)lg25 有谁会,
1个回答
=(2^4)^(3/4)×2^(-2)+lg(√2)²+1/2lg5²
=2+lg2+lg5
=2+lg10
=3
相关问题
计算16^(-3/4)+198^(lg1)+log0.5 4+2lg根号2+1/2 lg25
计算:2(lg根号2)^2+lg根号2×lg5+根号{(lg根号2)^2-2lg根号2+1}
计算:(1)lg25+lg2•lg50; (2)3
1.1^lg1+3倍根号64-0.5^-2+lg25+2lg2
1.计算:lg 25+2/3lg 8+lg 5×lg 20+lg^(2) 2
1.计算 lg25+2/3lg8+lg5×lg20+lg²2
麻烦问一下1/2lg32/49-4/3lg根号8+lg根号245 怎么会算成等于5/2lg2-lg7-2lg2+1/2l
0.25^(-2)+8^(2/3)-(1/16)^(-0.75)-lg25-lg2=?
上面是lg2+2/3lg4-lg根号2-lg8下面是lg64-lg16
计算:4lg1+lg2.5+lg4-(1/2)lg10^2