238÷238又239之238
=238÷（238×239+238）/239
=238÷239/[238×(239+1)]
=239/240
……
2001÷2001又2002分之2001+2003分之1
=2001÷（2001×2002+2001）/2002 + 1/2003
=2001×2002/[2001×(2002+1)] + 1/2003
=2002/2003+1/2003
=1
238÷238又239之238
=238÷（238×239+238）/239
=238÷239/[238×(239+1)]
=239/240
……
2001÷2001又2002分之2001+2003分之1
=2001÷（2001×2002+2001）/2002 + 1/2003
=2001×2002/[2001×(2002+1)] + 1/2003
=2002/2003+1/2003
=1