Question

计算:(-2a/b^2)^2*(b^3/4a^ 计算：(x+3/x^2-3x-x-1/x^2-6x+9)/x-9/x的值

Answer 1

:(-2a/b^2)^2*(b^3/4a^

=4a²/b^4×b³/4a²

=1/b

计算：(x+3/x^2-3x-x-1/x^2-6x+9)/x-9/x的值

原式=[(x+3)(x-3)/x(x-3)²-x(x-1)/x(x-3)²]÷x/(x-9)

=(x²-9-x²+x)/x(x-3)²×x/(x-9)

=(x-9)/x(x-3)²×x/(x-9)

=1/(x-3)²