楼上的似乎曲解题意了……
1.Counterexample:Let A = [1 1; 0 1] B = [1 0; 1 1],then (A-B)(A+B) = [1 2; -2 -1] while A^2-B^2 = [0 2; -2 0]
2.Let A = [0 1; 1 0] B=[1 0; 0 0],then AB = [0 0; 1 0] is not symmetric
楼上的似乎曲解题意了……
1.Counterexample:Let A = [1 1; 0 1] B = [1 0; 1 1],then (A-B)(A+B) = [1 2; -2 -1] while A^2-B^2 = [0 2; -2 0]
2.Let A = [0 1; 1 0] B=[1 0; 0 0],then AB = [0 0; 1 0] is not symmetric