(1)由题意得BC=36-2x,
∴S=x(36-2x)=-2x2+36x.
36−2x>x
36−2x≤20,
解得8≤x<12
∴S=-2x2+36x(8≤x<12);
(2)-2x2+36x=154,
2x2-36x+154=0,
x2-18x+77=0,
(x-7)(x-11)=0,
解得x1=7,x2=11,
∵8≤x<12,
∴x=11.
答:能,x的值为11.
(1)由题意得BC=36-2x,
∴S=x(36-2x)=-2x2+36x.
36−2x>x
36−2x≤20,
解得8≤x<12
∴S=-2x2+36x(8≤x<12);
(2)-2x2+36x=154,
2x2-36x+154=0,
x2-18x+77=0,
(x-7)(x-11)=0,
解得x1=7,x2=11,
∵8≤x<12,
∴x=11.
答:能,x的值为11.