Question

已知f（x）=-4x²+4ax-4a-a²在区间[0,1]内的最大值为-5,求a的值,

Answer 1

∵ f(x)=-4x^2+4ax-4a-a^2

x=-4a/-8=a/2

∴1)a/22

f(x)max=f(0)=-4a-a^2=-5

a=1 a=-5

∴a=-1 a=5/4