(2x+9)/(x+3)-1/(x-3)-2/x=2(2x+6+3)/(x+3)-1/(x-3)-2/x=22+ 3/(x+3)-1/(x-3)-2/x=2∴3/(x+3)-1/(x-3)-2/x=0
方程两边乘以x(x+3)(x-3)得3x(x-3)-x(x+3)-2(x+3)(x-3)=03x²-9x-x²-3x-2x²+18=0-12x=-18x=3/2检验：x=3/2是方程的解
看一下这个的处理方法
(2x+9)/(x+3)=[(2x+6)+3]/(x+3)=2(x+3)/(x+3) +3/(x+3)=2+ 3/(x+3)