x+y+z=2 (1)
4x+2y+z=4 (2)
2x+3y+z=1 (3)
(2)-(1)
3x+y=2 (4)
(2)-(3)
2x+y=3 (5)
(4)-(5)
所以
x=-1
y=3-2x=5
z=2-x-y=-2
x+y+z=2 4x+2y+z=4 2x+3y+z=1
2个回答
相关问题
-
2x-y=7 x+y+z=25x+3y+z=2 x-2y+z=-1 3x-4z=4 x+2y+3z=-1x+y-z=6x
-
解三元一次方程组1、x+y-z=4 2x-y+z=5 x-3y+z=-2 2、y+2z=-2 3x+y-4z=1 2x-
-
已知x+y+z=1 x2+y2+z2=2 x3+y3+z3=3 求x4+y4+z4=?
-
3x+y-2z=1,4x+2y-3z=1,2x-3y+4z=13
-
x+y+z=2 ① 2x+3y+z=38 ① x+y=3 3x-y-4z=5 ② 3x+4y+2z+56 ② y+z=5
-
x,y,z满足x+y+z=3,x^2+y^2+z^2=29,x^3+y^3+z^3=45,求x,y,z,x^4+y^4+
-
3x+2y+z=4 x+y+z=10 2x+3y-z=1
-
3x+2y+z=9 x-3y-2z=1 -x+4y+4z=5
-
设x、y、z为整数,证明:x^4*(y-z)+y^4*(z-x)+z^4*(x-y)/(y+z)^2+(z+x)^2+(