Question

4a^2-4(ab+4)+b^2 \\(x^2-2x)^2-2xy+x^2y \\ax(y^3+b^3)+by(bx^2

Answer 1

4a^2-4(ab+4)+b^2

=4a^2-4ab-16+b^2

=(4a^2-4ab+b^2)-4^2

=(2a-b)^2-4^2

=(2a-b+4)(2a-b-4)

(x^2-2x)^2-2xy+x^2y

=(x^2-2x)^2+y(x^2-2x)

=(x^2-2x)(x^2-2x+y)

=x(x-2)(x^2-2x+y)

ax(y^3+b^3)+by(bx^2+a^2y)

=axy^3+axb^3+b^2x^2y+a^2by^2

=(axy^3+b^2x^2y)+(axb^3+a^2by^2)

=xy(ay^2+b^2x)+ab(xb^2+ay^2)

=(xy+ab)(ay^2+b^2x)