log2(3) = lg3/lg2 = lg27/lg8 ;
log3(4) = lg4/lg3 = lg16/lg9 ;
因为,
log2(3)/log3(4) = (lg27/lg8)(lg9/lg16) = (lg27/lg16)(lg9/lg8) > 1 ,
所以,
log2(3) > log3(4) .
log2(3) = lg3/lg2 = lg27/lg8 ;
log3(4) = lg4/lg3 = lg16/lg9 ;
因为,
log2(3)/log3(4) = (lg27/lg8)(lg9/lg16) = (lg27/lg16)(lg9/lg8) > 1 ,
所以,
log2(3) > log3(4) .