原式=I1-1/2I+I1/2-1/3I+I1/3-1/4I+...I1/2009-1/2010I
=1-1/2+1/2-1/3+1/3-1/4+...+1/2009-1/2010
=2009/2010
｜1/2-1｜+｜1/3-1/2｜+1/4-1/3｜+...｜1/2009-1/2008｜+｜1/2010-1/2009
1个回答
相关问题
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(1/2010*1/2009*1/2008*...*1/3*1/2*1)^2011*(2010*2009*2008*..
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1*2*3*...*2009*2010.还有：2009/2008*2008/2007*...*2/3*2/1.
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计算 |1/2011-1/2010|+|1/2010-1/2009|+|1/2009-1/2008|+...+|1/3-
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2010*2010-2009*2009+2008*2008···················+2*2-1*1
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计算|1/2011-1/2010|+|1/2010-1/2009|+|1/2009-1/2008|+...+|1/2-1
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1/1*2+1/2*3+1/3*4+...+1/2007*2008+1/2008*2009
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1/2*1+1/3*2+1/4*3.+1/2009*2008=
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(1/2+1/3.+1/2009)*(1+1/2+1/3..+1/2008)-(1+1/2+1/3..+1/2009)*
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(-1*1/2)+(-2*1/3)+(-3/1*1/4)+...+(-1/2009*2010)+(-1/2010*1/2
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1/1*2+1/2*3+1/3*4+.1/2009*2010=?