设X=K
Y=2K
Z=3K
3X-4Y+5Z=3K-8K+15K=10K=12
K=1.2
3X-5Y+Z=3K-10K+3K=-4K=-4*1.2=-4.8
1.已知X:Y:Z=1:2:3,且3X-4Y+5Z=12,求解算式3X-5Y+Z的值.
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x-5y-3z=0 y+z-3x=3 x+y+3z=14 y+4z=3 z+x-3y=5 2x+y+z=7 2x-z=1