这个用的方法是裂项法,原式=1/2(1-1/3+1/3-1/5+1/5……-1/21)=1/2×(1-1/21)=10/21
请问,1/(1*3)+1/(3*5)+1/(5*7)+……+1/(17*19)+1/(19*21)怎么计算?
1个回答
相关问题
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1/3*1+1/3*5+1/5*7+A+1/17*19+1/19*21
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1*1/3+1/3*5+1/5*7+……+1/17*19+1/19*21要过程啊!
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1+3+5+7+···+21+23+21+19+17+···+7+5+3+1=?
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1/1X3+1/3X5+1/5X7...1/17X19+1/19X21=
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1/3+1/3*5+1/5*7+.+1/19*21
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1/1*3+1/3*5+1/5*7+1/7*9+.1/19*21怎么算
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计算:1.1+3.3+5.5+7.7+9.9+11.11+13.13+15.15+17.17+19.19=______.
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计算:1.1+3.3+5.5+7.7+9.9+11.11+13.13+15.15+17.17+19.19=______.
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计算:1.1+3.3+5.5+7.7+9.9+11.11+13.13+15.15+17.17+19.19=______.
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计算:1+3+5+7+9+11+13+15+17+19+21+23=______.