a1+a11=2a6
b1+b17=2b9
S11=(a1+a11)*11/2
T17=(b1+b17)*17/2
你确定题目没错吗?
等差数列an与bn的前n项和分别为sn与tn,且sn/tn=(2n+3）/（n+3）则a6/b9=?
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