计算:(—2ab²)的3次方×(3a²b)²+4a的3次方b²×18a的4次方b

1个回答

  • (-2ab²)^3×(3a²b)²+4a^3b²×18a^4b^6

    =-8a^3b^6×9a^4b^2+4a^3b²×18a^4b^6

    =-72a^(3+4)b^(6+2)+72a^(3+4)b(2+6)

    =-72a^7b^8+72a^7b^8

    =0

    1/2(x+y+z)^2+1/2(x-y-z)(x-y+z)-z(x+y)

    =[(x+y)^2+2z(x+y)+z^2]/2+[(x-y)^2-z^2]/2-[2z(x+y)]/2

    =[(x+y)^2+2z(x+y)+z^2+(x-y)^2-z^2-2z(x+y)]/2

    =[(x+y)^2+(x-y)^2]/2

    =[x^2+y^2+2xy+(x-y)^2]/2

    =[x^2+y^2-2xy+4xy+(x-y)^2]/2

    =[(x-y)^2+4xy+(x-y)^2]/2

    =[36+84+36]/2

    =36+42

    =78

    3(a+5)²+2(3—a)²+(9—a)(9+a)=0

    3a^2+30a+75+2a^2-12a+18+81-a^2=0

    4a^2+18a+174=0

    2a^2+9a+87=0

    △=9^2-4*2*87