Question

6个员工,一个人上网的概率为二分之一,则至少三个人上网的概率是多少?

Answer 1

C6,3(0.5^6)+C6,4(0.5^6)+C6,5(0.5^6)+C6,6(0.5^6)=(15+6+1)/64=22/64=21/32