(a-2)*(a^2-4)/(a^2-4a-+4)
1个回答
(a-2)*(a^2-4)/(a^2-4a+4)
=(a-2)*(a-2)*(a+2)/(a-2)^2
=(a-2)^2*(a+2)/(a-2)^2
=a+2
相关问题
a^2/(a^2-4) + 4/(a+2-a^2) + (4a-4)/(a^4-5a^2+4)
a^2/(a^-4)+4/(a+2-a^2)+(4a-4)/(a^4-5a^2+4)
分式的加减:a^2/a^2-4+4/a+2-a^2+4a-4/a^4-5a^2+4
(a^2-4)(a^2-2a+4)(a^2+2a+4)计算方式
(4a+1)∧2-16a∧2(4a^2+1)^2-16a^2=(4a^2+4a+1)(4a^2-4a+1)怎么变成这样
化简:(1−a2+8a2+4a+4)÷4a−4a2+2a.
[1-(6+3a)/(a2+4a+4)]÷[(4a-4)/(a2+2a)]
计算:(a+2a2−2a−a−1a2−4a+4)÷4−aa2−2a.
(a^2-4a+4)-4(a-2)+4因式分解
(a-2/a2+2a-a-1/a2+4a+4)/a-4/a+2,其中a满足a2+2a=1