已知,x ≥ 1 ,y ≥ 1 ,x+y ≤ 3 ,
可得：x+2 ≥ 3 ,1 / (x+2) ≤ 1/3 ,x+y+3 ≤ 6 ,
所以,z = (2x+y+5) / (x+2) = 1 + (x+y+3) / (x+2) ≤ 1+6*(1/3) = 3 ,
即：最大值为 3 .
若实数x,y满足x>=1,y>=1,x+y
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