(x-2)(x+2)(x^4+4x^2+16)
2个回答
=(x-2)×[(x²+4)²-4x²]×(x+2)
=(x-2)(x²+2x+4)(x²-2x+4)(x+2)
=(x³-8)(x³+8)
=x^6-64
相关问题
(4/X+2)+(16X^3/X^4-16)+(8X/X^2+4)+(4/X-2)
若x是根号16的算是平方根,求x^2(x^4+4x^2+16)-4(x^4+4x^2+16)
(x∧2-4x)∧2+16(x∧2-4x)+64
(2005•滨州)计算x4−16x4+8x2+16÷x2−x−2x2+4+x2+xx2+2x+1
(x^2-4x)(x^2-4x+8)+16
(x^2 + 4x)(x^2 + 4x+8)+16
(x-4x)^2+8(x^2-4x)+16
(x^2-16/x^2+8x+16) + (x/x-4)
x2-16 /x2+8x+16+x/x-4
(x-1/2)(2x+1)(2x^2+1/2)(4x^4+1/4)(16x^6+1/16)/(256x^16-1/256