Question

分解因式 p(x-y)+(-x+y)(2q-p)=

Answer 1

p(x-y)+(-x+y)(2q-p)

=p(x-y)-(x-y)(2q-p)

=(x-y)(p-2q+p)

=2(x-y)(p-q)

m^2(x-y)^2+mn(x-y)

=m(x-y)[m(x-y)+n]

=m(x-y)(mx-my+n)

y(x-y)-4(y-x)

=(x-y)(x+4)

x(1-x)+x^2(x-1)-x^3(x-1)

=x(x-1)(-1+x-x^2)

=-x(x-1)(x^2-x+1)