对f(x)求导得:f(x)′=2010(x-1)2009
∴当x<1时,f(x)′<0
当x>1时.f(x)′>0
f(x)在x=1时取极小值
∴靠近x=1处值小,
而[0.9^1.1-1]>[1.1^0.9-1]
∴1.1^0.9更靠近1
∴a>