因式分解:(X²+3X+2)(4X²+8x+3)-90;X9+X6+X3-3

1个回答

  • (x^2+3x+2)(4x^2+8x+3)-90

    =(x+1)(x+2)(2x+3)(2x+1)-90

    =[(x+1)(2x+3)][(x+2)(2x+1)]-90

    =(2x^2+5x+3)(2x^2+5x+2)-90

    =(2x^2+5x)^2+5(2x^2+5x)-84

    =(2x^2+5x-7)(2x^2+5x+12)

    =(x-1)(2x-7)(2x^2+5x+12)

    x^9+x^6+x^3-3

    =x^9-1+x^6+x^3-2

    =(x^3-1)(x^6+x^3+1)+(x^3+2)(x^3-1)

    =(x^3-1)[(x^6+x^3+1)+(x^3+2)]

    =(x-1)(x^2+x+1)(x^6+2x^3+3)