1/x+2/y+3/z=5,3/x+2/y+1/z=7,求1/x+1/y+1/z
1个回答
两个相加
4/x+4/y+4/z=12
两边除以4
1/x+1/y+1/z=3
相关问题
若(1/x)+(2/y)+(3/z)=5,(3/x)+(2/y)+(1/z)=7,则(1/x)+(1/y)+(1/z)=
已知1/X+2/Y+3/Z=5,3/X+2/Y+1/Z=7,求1/X+1/Y+1/Z的值
2x-y=7 x+y+z=25x+3y+z=2 x-2y+z=-1 3x-4z=4 x+2y+3z=-1x+y-z=6x
1.x+y+z=21,x-y=1,2x+z-y=13.2.3x+2y+z=13,x+y+2z=7 ,2z+3y-z=12
x-5y-3z=0 y+z-3x=3 x+y+3z=14 y+4z=3 z+x-3y=5 2x+y+z=7 2x-z=1
1.解下列方程(1)(x+y=-2(x+z=13(y+z=1(2)(x-y-z=-1(3x+5y+7z=11(4x-y+
(|x-2|+|x-1|)(|y-3|+|y+1|)(|z-1|+|z+1|)=8,求x+y+z
三元一次方程 X-y-z=-1 3x+5y+7z=11 4x-y+2z=-1 X=?Y=?Z=?
若x+y+z=2,x^2+y^2+z^2=2,1/x+1/y+1/z=1/3则 x^3+y^3+z^3=
y-3x-2z=1,x+2y+3z=9,5x-7y+z=34