1、设x/3=y/2=z/5=k,则x=15k,y=10k,z=25k,所以,(xy+yz+zx)/(x²+y²+z²)=(150k²+250k²+375k²)/(225k²+100k²+625k²)=31/38.
2、(1-a)/ab=3,则ab=(1-a)/3,则[(3a-1)(3b+1)+1]/[b-a+12ab]=[9ab-3b+3a]/[12ab-a+b]=[3(1-a)+3a-3b]/[4(1-a)-a+b]=(3-3b)/(4-5a+b)=……….
1、设x/3=y/2=z/5=k,则x=15k,y=10k,z=25k,所以,(xy+yz+zx)/(x²+y²+z²)=(150k²+250k²+375k²)/(225k²+100k²+625k²)=31/38.
2、(1-a)/ab=3,则ab=(1-a)/3,则[(3a-1)(3b+1)+1]/[b-a+12ab]=[9ab-3b+3a]/[12ab-a+b]=[3(1-a)+3a-3b]/[4(1-a)-a+b]=(3-3b)/(4-5a+b)=……….