Question

当m为何整数时,分式6m+3/2m-1的值也为整数

Answer 1

解析,

设t=(6m+3)/(2m-1)

=[3(2m-)+6]/(2m-1)

=3+6/(2m-1)

t是整数,即是,6/(2m-1)为整数,

故,m=-1,0,1,或2.