y=x-3,5x+3y+2z=1,x+z=-1
1个回答
y=x-3,5x+3y+2z=1,x+z=-1
由x+z=-1得 z=-1-x
则把y,z带入得
5x+3(x-3)+2(-1-x)=1
6x=12
则x=2
则y=-1
z=-3
相关问题
x-5y-3z=0 y+z-3x=3 x+y+3z=14 y+4z=3 z+x-3y=5 2x+y+z=7 2x-z=1
x、y、z满足3x+2y+z=5,2x+y-3z=1.
解三元一次方程组1)2x+y-3z=3,3x-y+2z=1,x-y-z=5 2)x:y=3:2,y:z=5:4,x+y+
3x-5y+2z=1 4x+5y-z=5 x-5y+3z=-2
解三元一次方程 (1) x-2y=1 (2) x+y-z=11 x=3y y+z-x=5 x-3y+z=8 z+x-y=
1/x+2/y+3/z=5,3/x+2/y+1/z=7,求1/x+1/y+1/z
3x+2y+z=14 ,x+y+z=10,z+2x+3y=1 5
方程 {3x+3y+z=6 {x-y-2z=-1 {x+2y-z=5
x+y+z=3(1) x+2y+3z=6(2) 2x+y+2z=5(3)
一1 .x+z-3=02 .2x-y+2z=23 x-y-z= -3二1.2x+4y+3z=92 3x-2y=5z=11