y=3sin(2x+π/4)=3sin[2(x+π

y=3sin(2x+π/4)=3sin[2(x+π/8)] 为什么

2个回答

2sin（πx/4-π/4）+6＜2sin（πx/4-3π/4）+8
y=sin(π/4+x/2)sin(π/4-x/2) =sin(π/4+x/2)sin[π/2-(π/4+x/2)]
y=2sin三分之一x y=4sin(x-π/3) y=sin(2x+π/6) y=3sin(1/2x-π/4) 的周期
求函数y=[sin2x+sin(2x+π/3)-cos1/2﹙π-4x﹚]/[cos2x+cos﹙2x+π/3﹚-sin
sin2x*cosπ/3+sin2x*cosπ/3 为什么等于sin2x
求值域（1)y=2sin(x/2+π/4)x∈[0,π) (2)y=2cosx-sin^2x+3 x∈[-π/3,2/
y=2cos(x/4+ π/3)-3sin(x- π/4)
为什么f(x)=sin(2x- π/3 )+√3 cos(2x- π/3 )=2sin2x
f(x)=1-2sin^2(x+π/8)+2sin(x+π/8)*cos(x+π/8)=cos(2x+π/4)+sin(
y=3sin(2x+π/5)怎么变化得到y=2sin(2x+π/4)