(lg2)^2+lg5lg20-1
1个回答
=(lg2)^2+lg5(lg5+lg4)-1
=(lg2)^2+(lg5)^2+2*lg5*lg2-1
=(lg2+lg5)^2-1
=1-1
=0
相关问题
1、lg5^2+2/3lg8+lg5lg20+(lg2)^2
lg2*lg50 + lg20*lg5 - 2lg5*lg2=?
(lg2)^2+lg5·lg20-1=?
为什么lg5*lg20=lg5*(1+lg2)
lg20乘lg5的计算lg20乘lg5为什么等于(1+lg2)*(1-lg2)
2lg5+lg20=?lg5*lg20=?
lg^2 5+lg2*lg5+lg20=
lg5^2+lg4+lg5*lg20+(lg2)^@
lg5^2+lg4+lg5*lg20+(lg2)^2
(lg2)^2+lg20*lg5+(lg5)^2