Question

方程[X^2-x*根号（2x^2-3)=2-x]的实数解是?

Answer 1

X^2-x*√（2x^2-3)=2-x

x+1-2/x =√（2x^2-3)

(x+1-2/x )^2=（2x^2-3)

(x^2-2)(x^2-2x+2)=0

x=±√2

2x^2-3≥0 x^2≥3/2 x=±√2满足

故：方程[X^2-x*根号（2x^2-3)=2-x]的实数解是x=±√2