如图所示,若有一只容积为3×10-4m3的瓶内盛有 - 知识问答

如图所示,若有一只容积为3×10-4m3的瓶内盛有0.2kg的水,

4个回答

1,
V水=m水/ρ水
=0.2/1
=0.2dm^3
=200cm^3 (ρ水=1g/cm^3=1000kg/m^3)
V石个=（300-200）/25
=4cm^3 (3×10-4m3=300cm^3)
ρ石=m石/V石
=10/4
=2.5g/cm^3
=2.5*10^3kg/m^3

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