一、用代入法解下列方程组 1、{x+y+z=2,3x-y-4z=5 ,2x+3y-2z=0}
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  • 1.z=38-2x-3y

    3x+4y+2(38-2x-3y)=56

    -x-2y=-20

    x+2y=20

    4x+5y+38-2x-3y=66

    2x+2y=28

    x+y=14

    y=14-x

    x+2(14-x)=20

    -x=-8

    x=8

    y=6

    z=4

    2.z=9-2x-3y

    3x+4(9-2x-3y)=7

    3x+36-8x-12y=7

    -5x-12y=-29

    5x+12y=29

    5x-9y+7(9-2x-3y)=8

    5x-9y+63-14x-21y=8

    -9x-30y=-55

    9x+30y=55

    x=1/5(29-12y)

    9/5(29-12y)+30y=55

    9(29-12y)+150y=275

    9*29-108y+150y=275

    42y=275-9*29=14

    y=1/3

    x=1/5(29-4)=5

    z=9-10-1=-2

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