Question

分式的加减：1/(x-5) - 6/(x^2-25) -(x+1)/(10+2x)

Answer 1

1/(x-5)-6/(x^2-25)-(x+1)/(10+2x)

=2(x+5)/2(x^2-25)-12/2(x^2-25)-2(x+1)(x-5)/2(x^2-25)

=[2x+10-12-2(x^2-4x-5)]/2(x^2-25)

=(2x-2-2x^2+6x+10)/2(x^2-25)

=(8x-2x^2+8)/2(x^2-25)

=(4x-x^2+4)/(x^2-25)