(1)由已知可得
X^2-xy-2y^2=0
即(x+y)(x-2y)=0
∴x+y=0 或x-2y=0
∴B={(x,y)|x+y=0或x-2y=0}
∴C∈B,D∈B
C∩D={(0,0)}
(2)由A得
X^2/15/4-(y+1/2)^2/15/4=1
∴A∩B={(4,-4)}或{(-2,-1),(8/3,4/3)}
(1)由已知可得
X^2-xy-2y^2=0
即(x+y)(x-2y)=0
∴x+y=0 或x-2y=0
∴B={(x,y)|x+y=0或x-2y=0}
∴C∈B,D∈B
C∩D={(0,0)}
(2)由A得
X^2/15/4-(y+1/2)^2/15/4=1
∴A∩B={(4,-4)}或{(-2,-1),(8/3,4/3)}