Question

4x/(x²-4)-（2x+6)/(x²+x-6)=1-(x-3)/(x²-x-6)

Answer 1

原方程即：

4x/[(x-2)(x+2)]-2(x+3)/[(x+3)(x-2)]=1-(x-3)/[(x-3)(x+2)]

化简后得：

4x/[(x-2)(x+2)]-2/(x-2)=(x+1)/(x+2)

两边乘以(x-2)(x+2)得：

(x-1)(x-2)=0

即 x=1 或 x=2