由log 2x+log 2(3•2 n-1-x)≥2n-1得到2 n-1∵x是正整数∴a n=2•2 n-1 - 2 n-1 +1= 2 n-1 +1, ∴S n=
1- 2 n
1-2 +n=2 n+n-1
故选A.