df=ydx+xdy+cos(x+2y)(dx+2dy)
=[y+cos(x+2y)]dx+[x+2cos(x+2y)]dy
所以:
df(1,2)=(2+cos5)dx+(1+2cos5)dy.
即方向导数为:((2+cos5),(1+2cos5))
df=ydx+xdy+cos(x+2y)(dx+2dy)
=[y+cos(x+2y)]dx+[x+2cos(x+2y)]dy
所以:
df(1,2)=(2+cos5)dx+(1+2cos5)dy.
即方向导数为:((2+cos5),(1+2cos5))