用三要素法求解.
iL(0)=0,iL(∞)=1A,断开电感,断开电流源,求等效内阻
R=5Ω+5Ω=10Ω
τ=L/R=0.5H/10Ω=0.05s
iL(t)= iL(∞)+[ iL(0)- iL(∞)]e∧-t/τ
=1A+[0-1A]e∧-t/0.05
=(1-e∧-20t)A
uL(t)=Ldi/dt=0.05[-(-20)]e∧-20tV=e∧-20tV
用三要素法求解.
iL(0)=0,iL(∞)=1A,断开电感,断开电流源,求等效内阻
R=5Ω+5Ω=10Ω
τ=L/R=0.5H/10Ω=0.05s
iL(t)= iL(∞)+[ iL(0)- iL(∞)]e∧-t/τ
=1A+[0-1A]e∧-t/0.05
=(1-e∧-20t)A
uL(t)=Ldi/dt=0.05[-(-20)]e∧-20tV=e∧-20tV