2H2+O2=2H2O 2CO+O2=2CO2 CH4+2O2=CO2+2H2O
设H2=0.25VL CO=0.25VL CH4=0.5VL
1LH2消耗O2 0.125VL 1LCO消耗O2 0.125VL 2LCH4消耗O2 1VL
所以共消耗O2 1.25V
2H2+O2=2H2O 2CO+O2=2CO2 CH4+2O2=CO2+2H2O
设H2=0.25VL CO=0.25VL CH4=0.5VL
1LH2消耗O2 0.125VL 1LCO消耗O2 0.125VL 2LCH4消耗O2 1VL
所以共消耗O2 1.25V