令a=X/2=Y/3=Z/4
X=2a
Y=3a
Z=4a
所以原式=(4a+9a-4a)/(2a+6a-12a)
=9a/(-4a)
=-9/4
已知X/2=Y/3=Z/4≠0,求2x+3y-z/x+2y-3z
1个回答
相关问题
-
已知3x-4y-z=0.2x+y-z=0,且xyz=0,求x+2y-3z/3x-2y+3z
-
已知3x+4y+5z=0,2x+3y-4z=0,求(x+y+z)/(x-y+z)
-
已知x+2y-4z=0,3x-y-z=0,则3x+2y+z/x+2y+z=
-
已知x+y+z=1 x2+y2+z2=2 x3+y3+z3=3 求x4+y4+z4=?
-
已知2X-Y+Z=0.X+3Y-4Z=0,求x :y :z
-
已知x+4y+3z=3x-2y-5z=0,求x+2y-z/2x-3y+7z的值
-
已知x+2y+3z=2 3x+y+2z=3 2x+3y+z=4求X+Y+Z的值
-
已知：x+2y+3z=2,3x+y+2z=3,2x+3y+z=4,求x+y+z的值
-
已知xyz满足x-2y+3z=0,2x-3y+4z=0,求x:y:z
-
已知:x-2y+4z=0,4x-3y+z=0,求2x²+y²+z²/x²+2y²+7z²