关于x的方程(m+2)x^(|m|-1)+5=0 是一元一次方程
m+2≠0,且|m|-1=1
m≠-2,且|m|=2
∴m=2
(5x+3m)/3 - (mx-3)/(2m) = 1
(5x+6)/3 - (2x-3) /4 = 1
4(5x+6) - 3(2x-3) = 12
20x+24-6x+9 = 12
14x = -21
x = -21/14 = -3/2
关于x的方程(m+2)x^(|m|-1)+5=0 是一元一次方程
m+2≠0,且|m|-1=1
m≠-2,且|m|=2
∴m=2
(5x+3m)/3 - (mx-3)/(2m) = 1
(5x+6)/3 - (2x-3) /4 = 1
4(5x+6) - 3(2x-3) = 12
20x+24-6x+9 = 12
14x = -21
x = -21/14 = -3/2