f(x)=m*n=√3sinx/4cosx/4+cos²x/4
=√3/2sinx/2+1/2cosx/2+1/2
=cos(x/2-π/3)+1/2
f(a)=3/2,
cos(a/2-π/3)+1/2=2/3
cos(a/2-π/3)=1
cos(2π/3-a)=cos(a-2π/3)
=2cos^2(a/2-π/3)-1
=2*1^2-1
=1
f(x)=m*n=√3sinx/4cosx/4+cos²x/4
=√3/2sinx/2+1/2cosx/2+1/2
=cos(x/2-π/3)+1/2
f(a)=3/2,
cos(a/2-π/3)+1/2=2/3
cos(a/2-π/3)=1
cos(2π/3-a)=cos(a-2π/3)
=2cos^2(a/2-π/3)-1
=2*1^2-1
=1